第一套
===============================================================================
試題說明 :
===============================================================================
已知在檔案中存有若干個(個數<200)四位數字的正整數, 函式ReadDat( )是讀取這若干個正整數並存入陣列xx中。請編制函式CalValue( ), 其功能要求: 1. 求出這檔案中共有多少個正整數totNum; 2.求出這些數中的各位數字之和是偶數的數的個數totCnt, 以及滿足此條件的這些數的算術平均值totPjz, 最後呼叫函式WriteDat()把所求的結果輸出到檔案中。
注意: 部分源程式存放在PROG1.C中。
請勿改動主函式main( )、讀資料函式ReadDat()和輸出資料
函式WriteDat()的內容。
===============================================================================
程式 :
===============================================================================
#include
#include
#define MAXNUM 200
int xx[MAXNUM] ;
int totNum = 0 ; /* 檔案中共有多少個正整數 */
int totCnt = 0 ; /* 符合條件的正整數的個數 */
double totPjz = 0.0 ; /* 平均值 */
int ReadDat(void) ;
void WriteDat(void) ;
void CalValue(void)
{
}
void main()
{
clrscr() ;
if(ReadDat()) {
printf("資料檔案不能開啟!07n") ;
return ;
}
CalValue() ;
printf("檔案中共有正整數=%d個n", totNum) ;
printf("符合條件的正整數的個數=%d個n", totCnt) ;
printf("平均值=%.2lfn", totPjz) ;
WriteDat() ;
}
int ReadDat(void)
{
FILE *fp ;
int i = 0 ;
if((fp = fopen("", "r")) == NULL) return 1 ;
while(!feof(fp)) {
fscanf(fp, "%d,", &xx[i++]) ;
}
fclose(fp) ;
return 0 ;
}
void WriteDat(void)
{
FILE *fp ;
fp = fopen("", "w") ;
fprintf(fp, "%dn%dn%.2lfn", totNum, totCnt, totPjz) ;
fclose(fp) ;
}
===============================================================================
所需資料 :
===============================================================================
@2 016
6045,6192,1885,3580,8544,6826,5493,8415,3132,5841,
6561,3173,9157,2895,2851,6082,5510,9610,5398,5273,
3438,1800,6364,6892,9591,3120,8813,2106,5505,1085,
5835,7295,6131,9405,6756,2413,6274,9262,5728,2650,
6266,5285,7703,1353,1510,2350,4325,4392,7573,8204,
7358,6365,3135,9903,3055,3219,3955,7313,6206,1631,
5869,5893,4569,1251,2542,5740,2073,9805,1189,7550,
4362,6214,5680,8753,8443,3636,4495,9643,3782,5556,
1018,9729,8588,2797,4321,4714,9658,8997,2080,5912,
9968,5558,9311,7047,6138,7618,5448,1466,7075,2166,
4025,3572,9605,1291,6027,2358,1911,2747,7068,1716,
9661,5849,3210,2554,8604,8010,7947,3685,2945,4224,
7014,9058,6259,9503,1615,1060,7787,8983,3822,2471,
5146,7066,1029,1777,7788,2941,3538,2912,3096,7421,
9175,6099,2930,4685,8465,8633,2628,7155,4307,9535,
4274,2857,6829,6226,8268,9377,9415,9059,4872,6072,
#E
@3 $ 003
|160|91|5517.16
#E
第二套
===============================================================================
試題說明 :
===============================================================================
已知在檔案中存有若干個(個數<200)四位數字的正整數, 函式ReadDat( )編制函式CalValue( ), 其功能要求: 1. 求出這檔案中共有多少個正整數totNum; 2.求出這些數中的各位數字之和是奇數的數的個數totCnt, 以及滿足此條件的這些數的算術平均值totPjz, 最後呼叫函式WriteDat()把所求的結果輸出到檔案中。
注意: 部分源程式存放在PROG1.C中。
請勿改動主函式main( )、讀資料函式ReadDat()和輸出資料
函式WriteDat()的內容。
===============================================================================
程式 :
===============================================================================
#include
#include
#define MAXNUM 200
int xx[MAXNUM] ;
int totNum = 0 ; /* 檔案中共有多少個正整數 */
int totCnt = 0 ; /* 符合條件的正整數的個數 */
double totPjz = 0.0 ; /* 平均值 */
int ReadDat(void) ;
void WriteDat(void) ;
void CalValue(void)
{
}
void main()
{
clrscr() ;
if(ReadDat()) {
printf("資料檔案不能開啟!07n") ;
return ;
}
CalValue() ;
printf("檔案中共有正整數=%d個n", totNum) ;
printf("符合條件的正整數的個數=%d個n", totCnt) ;
printf("平均值=%.2lfn", totPjz) ;
WriteDat() ;
}
int ReadDat(void)
{
FILE *fp ;
int i = 0 ;
if((fp = fopen("", "r")) == NULL) return 1 ;
while(!feof(fp)) {
fscanf(fp, "%d,", &xx[i++]) ;
}
fclose(fp) ;
return 0 ;
}
void WriteDat(void)
{
FILE *fp ;
fp = fopen("", "w") ;
fprintf(fp, "%dn%dn%.2lfn", totNum, totCnt, totPjz) ;
fclose(fp) ;
}
===============================================================================
所需資料 :
===============================================================================
@2 016
6045,6192,1885,3580,8544,6826,5493,8415,3132,5841,
6561,3173,9157,2895,2851,6082,5510,9610,5398,5273,
3438,1800,6364,6892,9591,3120,8813,2106,5505,1085,
5835,7295,6131,9405,6756,2413,6274,9262,5728,2650,
6266,5285,7703,1353,1510,2350,4325,4392,7573,8204,
7358,6365,3135,9903,3055,3219,3955,7313,6206,1631,
5869,5893,4569,1251,2542,5740,2073,9805,1189,7550,
4362,6214,5680,8753,8443,3636,4495,9643,3782,5556,
1018,9729,8588,2797,4321,4714,9658,8997,2080,5912,
9968,5558,9311,7047,6138,7618,5448,1466,7075,2166,
4025,3572,9605,1291,6027,2358,1911,2747,7068,1716,
9661,5849,3210,2554,8604,8010,7947,3685,2945,4224,
7014,9058,6259,9503,1615,1060,7787,8983,3822,2471,
5146,7066,1029,1777,7788,2941,3538,2912,3096,7421,
9175,6099,2930,4685,8465,8633,2628,7155,4307,9535,
4274,2857,6829,6226,8268,9377,9415,9059,4872,6072,
#E
@3 $ 003
|160|69|5460.51
#E
第三套
===============================================================================
試題說明 :
===============================================================================
已知在檔案中存有若干個(個數<200)四位數字的正整數, 函式ReadDat( )是讀取這若干個正整數並存入陣列xx中。請編制函式CalValue( ), 其功能要求: 1. 求出這檔案中共有多少個正整數totNum; 2. 求這些數右移1位後, 產生的新數是奇數的數的個數totCnt, 以及滿足此條件的.這些數(右移前的值)的算術平均值totPjz, 最後呼叫函式WriteDat()把所求的結果輸出到檔案中。
注意: 部分源程式存放在PROG1.C中。
請勿改動主函式main( )、讀資料函式ReadDat()和輸出資料
函式WriteDat()的內容。
===============================================================================
程式 :
===============================================================================
#include
#include
#define MAXNUM 200
int xx[MAXNUM] ;
int totNum = 0 ; /* 檔案中共有多少個正整數 */
int totCnt = 0 ; /* 符合條件的正整數的個數 */
double totPjz = 0.0 ; /* 平均值 */
int ReadDat(void) ;
void WriteDat(void) ;
void CalValue(void)
{
}
void main()
{
clrscr() ;
if(ReadDat()) {
printf("資料檔案不能開啟!07n") ;
return ;
}
CalValue() ;
printf("檔案中共有正整數=%d個n", totNum) ;
printf("符合條件的正整數的個數=%d個n", totCnt) ;
printf("平均值=%.2lfn", totPjz) ;
WriteDat() ;
}
int ReadDat(void)
{
FILE *fp ;
int i = 0 ;
if((fp = fopen("", "r")) == NULL) return 1 ;
while(!feof(fp)) {
fscanf(fp, "%d,", &xx[i++]) ;
}
fclose(fp) ;
return 0 ;
}
void WriteDat(void)
{
FILE *fp ;
fp = fopen("", "w") ;
fprintf(fp, "%dn%dn%.2lfn", totNum, totCnt, totPjz) ;
fclose(fp) ;
}
===============================================================================
所需資料 :
===============================================================================
@2 016
6045,6192,1885,3580,8544,6826,5493,8415,3132,5841,
6561,3173,9157,2895,2851,6082,5510,9610,5398,5273,
3438,1800,6364,6892,9591,3120,8813,2106,5505,1085,
5835,7295,6131,9405,6756,2413,6274,9262,5728,2650,
6266,5285,7703,1353,1510,2350,4325,4392,7573,8204,
7358,6365,3135,9903,3055,3219,3955,7313,6206,1631,
5869,5893,4569,1251,2542,5740,2073,9805,1189,7550,
4362,6214,5680,8753,8443,3636,4495,9643,3782,5556,
1018,9729,8588,2797,4321,4714,9658,8997,2080,5912,
9968,5558,9311,7047,6138,7618,5448,1466,7075,2166,
4025,3572,9605,1291,6027,2358,1911,2747,7068,1716,
9661,5849,3210,2554,8604,8010,7947,3685,2945,4224,
7014,9058,6259,9503,1615,1060,7787,8983,3822,2471,
5146,7066,1029,1777,7788,2941,3538,2912,3096,7421,
9175,6099,2930,4685,8465,8633,2628,7155,4307,9535,
4274,2857,6829,6226,8268,9377,9415,9059,4872,6072,
#E
@3 $ 003
|160|80|5537.54
#E 第四套
===============================================================================
試題說明 :
===============================================================================
已知在檔案中存有若干個(個數<200)四位數字的正整數, 函式ReadDat( )是讀取這若干個正整數並存入陣列xx中。請編制函式CalValue( ), 其功能要求: 1. 求出這檔案中共有多少個正整數totNum; 2. 求這些數右移1位後, 產生的新數是偶數的數的個數totCnt, 以及滿足此條件的這些數(右移前的值)的算術平均值totPjz, 最後呼叫函式WriteDat()把所求的結果輸出到檔案中。
注意: 部分源程式存放在PROG1.C中。
請勿改動主函式main( )、讀資料函式ReadDat()和輸出資料
函式WriteDat()的內容。
===============================================================================
程式 :
===============================================================================
#include
#include
#define MAXNUM 200
int xx[MAXNUM] ;
int totNum = 0 ; /* 檔案中共有多少個正整數 */
int totCnt = 0 ; /* 符合條件的正整數的個數 */
double totPjz = 0.0 ; /* 平均值 */
int ReadDat(void) ;
void WriteDat(void) ;
void CalValue(void)
{
}
void main()
{
clrscr() ;
if(ReadDat()) {
printf("資料檔案不能開啟!07n") ;
return ;
}
CalValue() ;
printf("檔案中共有正整數=%d個n", totNum) ;
printf("符合條件的正整數的個數=%d個n", totCnt) ;
printf("平均值=%.2lfn", totPjz) ;
WriteDat() ;
}
int ReadDat(void)
{
FILE *fp ;
int i = 0 ;
if((fp = fopen("", "r")) == NULL) return 1 ;
while(!feof(fp)) {
fscanf(fp, "%d,", &xx[i++]) ;
}
fclose(fp) ;
return 0 ;
}
void WriteDat(void)
{
FILE *fp ;
fp = fopen("", "w") ;
fprintf(fp, "%dn%dn%.2lfn", totNum, totCnt, totPjz) ;
fclose(fp) ;
}
===============================================================================
所需資料 :
===============================================================================
@2 016
6045,6192,1885,3580,8544,6826,5493,8415,3132,5841,
6561,3173,9157,2895,2851,6082,5510,9610,5398,5273,
3438,1800,6364,6892,9591,3120,8813,2106,5505,1085,
5835,7295,6131,9405,6756,2413,6274,9262,5728,2650,
6266,5285,7703,1353,1510,2350,4325,4392,7573,8204,
7358,6365,3135,9903,3055,3219,3955,7313,6206,1631,
5869,5893,4569,1251,2542,5740,2073,9805,1189,7550,
4362,6214,5680,8753,8443,3636,4495,9643,3782,5556,
1018,9729,8588,2797,4321,4714,9658,8997,2080,5912,
9968,5558,9311,7047,6138,7618,5448,1466,7075,2166,
4025,3572,9605,1291,6027,2358,1911,2747,7068,1716,
9661,5849,3210,2554,8604,8010,7947,3685,2945,4224,
7014,9058,6259,9503,1615,1060,7787,8983,3822,2471,
5146,7066,1029,1777,7788,2941,3538,2912,3096,7421,
9175,6099,2930,4685,8465,8633,2628,7155,4307,9535,
4274,2857,6829,6226,8268,9377,9415,9059,4872,6072,
#E
@3 $ 003
|160|80|5447.93
#E 第五套
===============================================================================
試題說明 :
===============================================================================
已知在檔案中存有若干個(個數<200)四位數字的正整數, 函式ReadDat( )是讀取這若干個正整數並存入陣列xx中。請編制函式CalValue( ), 其功能要求: 1. 求出這檔案中共有多少個正整數totNum; 2. 求這些數中的個位數位置上的數字是3、6和9的數的個數totCnt, 以及滿足此條件的這些數的算術平均值totPjz, 最後呼叫函式WriteDat( )把所求的結果輸出到檔案中。
注意: 部分源程式存放在PROG1.C中。
請勿改動主函式main( )、讀資料函式ReadDat()和輸出資料
函式WriteDat()的內容。
===============================================================================
程式 :
===============================================================================
#include
#include
#define MAXNUM 200
int xx[MAXNUM] ;
int totNum = 0 ; /* 檔案中共有多少個正整數 */
int totCnt = 0 ; /* 符合條件的正整數的個數 */
double totPjz = 0.0 ; /* 平均值 */
int ReadDat(void) ;
void WriteDat(void) ;
void CalValue(void)
{
}
void main()
{
clrscr() ;
if(ReadDat()) {
printf("資料檔案不能開啟!07n") ;
return ;
}
CalValue() ;
printf("檔案中共有正整數=%d個n", totNum) ;
printf("符合條件的正整數的個數=%d個n", totCnt) ;
printf("平均值=%.2lfn", totPjz) ;
WriteDat() ;
}
int ReadDat(void)
{
FILE *fp ;
int i = 0 ;
if((fp = fopen("", "r")) == NULL) return 1 ;
while(!feof(fp)) {
fscanf(fp, "%d,", &xx[i++]) ;
}
fclose(fp) ;
return 0 ;
}
void WriteDat(void)
{
FILE *fp ;
fp = fopen("", "w") ;
fprintf(fp, "%dn%dn%.2lfn", totNum, totCnt, totPjz) ;
fclose(fp) ;
}
===============================================================================
所需資料 :
===============================================================================
@2 016
6045,6192,1885,3580,8544,6826,5493,8415,3132,5841,
6561,3173,9157,2895,2851,6082,5510,9610,5398,5273,
3438,1800,6364,6892,9591,3120,8813,2106,5505,1085,
5835,7295,6131,9405,6756,2413,6274,9262,5728,2650,
6266,5285,7703,1353,1510,2350,4325,4392,7573,8204,
7358,6365,3135,9903,3055,3219,3955,7313,6206,1631,
5869,5893,4569,1251,2542,5740,2073,9805,1189,7550,
4362,6214,5680,8753,8443,3636,4495,9643,3782,5556,
1018,9729,8588,2797,4321,4714,9658,8997,2080,5912,
9968,5558,9311,7047,6138,7618,5448,1466,7075,2166,
4025,3572,9605,1291,6027,2358,1911,2747,7068,1716,
9661,5849,3210,2554,8604,8010,7947,3685,2945,4224,
7014,9058,6259,9503,1615,1060,7787,8983,3822,2471,
5146,7066,1029,1777,7788,2941,3538,2912,3096,7421,
9175,6099,2930,4685,8465,8633,2628,7155,4307,9535,
4274,2857,6829,6226,8268,9377,9415,9059,4872,6072,
#E
@3 $ 003
|160|43|5694.58
#E
